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x^2-7x=9x-2
We move all terms to the left:
x^2-7x-(9x-2)=0
We get rid of parentheses
x^2-7x-9x+2=0
We add all the numbers together, and all the variables
x^2-16x+2=0
a = 1; b = -16; c = +2;
Δ = b2-4ac
Δ = -162-4·1·2
Δ = 248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{248}=\sqrt{4*62}=\sqrt{4}*\sqrt{62}=2\sqrt{62}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{62}}{2*1}=\frac{16-2\sqrt{62}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{62}}{2*1}=\frac{16+2\sqrt{62}}{2} $
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